我使用外部服务来拉一个组织(GetEvents)的事件。被返回的示例:
I’m using an external service to pull the events of an organisation (GetEvents). Example of what is returned:
{
"Result":"success",
"Key":"12345",
"Data":[
{"ID":"GFDCV34","lastChangedDate":"2015-12-03 11:14:27"},
{"ID":"IDJHE23","lastChangedDate":"2015-12-03 15:17:47"},
{"ID":"KDJBD34","lastChangedDate":"2015-12-03 05:25:11"}
]
}
接下来,我可以拉一个特定事件(GetEventDetails)的详细信息。事件的ID是必需的数据参数。我做了一个函数 getdetails(ID); 返回的细节。例如, getdetails('KDJBD34'),它给我:
Next, I can pull details of a certain event (GetEventDetails). The ID of the event is required as data parameter. I made a function getdetails(id); that returns the details.
For example, for getdetails('KDJBD34'), it gives me:
{
"Result":"success",
"Key":"52523",
"Data":[
{
"ID": "KDJBD34",
"name": "Name of event 3",
"date": "date of event 3",
"location": "location of event 3",
"lastChangedDate":"2015-12-03 05:25:11"
}
]
}
我要建立一个包含所有活动及其详细信息,像这样的数组:
I want to construct an array containing all the events and their details, like this:
{
"Result": "success",
"Key": "12345",
"Data":[
{
"ID": "GFDCV34",
"name": "Name of event 1",
"date": "date of event 1",
"location": "location of event 1",
"lastChangedDate": "2015-12-03 11:14:27"
},
{
"ID": "IDJHE23",
"name": "Name of event 2",
"date": "date of event 2",
"location": "location of event 2",
"lastChangedDate": "2015-12-03 15:17:47"
},
{
"ID": "KDJBD34",
"name": "Name of event 3",
"date": "date of event 3",
"location": "location of event 3",
"lastChangedDate":"2015-12-03 05:25:11"
}
]
}
任何谁可以点我在正确的方向?
Anyone who can point me in the right direction?
您应该通过你的第一个结果操作和附加新的检索性能
You should operate through your first results and attach the new retrieved properties
var res = {
"Result": "success",
"Key": "12345",
"Data": [{
"ID": "GFDCV34",
"lastChangedDate": "2015-12-03 11:14:27"
}, {
"ID": "IDJHE23",
"lastChangedDate": "2015-12-03 15:17:47"
}, {
"ID": "KDJBD34",
"lastChangedDate": "2015-12-03 05:25:11"
}]
};
var tmp;
res.Data.map(function(val,i){
tmp = getdetails(val.ID);
Object.keys(tmp.Data[0]).map(function(v,j){
val[v] = tmp.Data[0][v];
});
});
演示